Question

3x3 + 7x divided by 7 + 3x by long division

Answer 1

Answer:

(3x - 1) • (x + 1) • (x - 3)

Step-by-step explanation:

Step by step solution :

Step  1  :

Equation at the end of step  1  :

 (((3 • (x3)) -  7x2) -  7x) +  3

Step  2  :

Equation at the end of step  2  :

 ((3x3 -  7x2) -  7x) +  3

Step  3  :

Checking for a perfect cube :

3.1    3x3-7x2-7x+3  is not a perfect cube  

Trying to factor by pulling out :

3.2      Factoring:  3x3-7x2-7x+3  

Thoughtfully split the expression at hand into groups, each group having two terms :

Group 1:  -7x+3  

Group 2:  -7x2+3x3  

Pull out from each group separately :

Group 1:   (-7x+3) • (1) = (7x-3) • (-1)

Group 2:   (3x-7) • (x2)

Answer 2

SOLUTION

Long division in attachment

As remainder is not zero so(7+3x) is not a factor of (3x^3+7x).

By remainder theorem

put 7+3x=0 we get

x= -7/3 now for checking out the remainder put x= -7/3 in (3x^3 +7x)

We get, f(-7/3) = 3(-7/3)^3 + 7(-7/3)

=) f(-7/3)= - (343/9) - (49/3)f (-7/3) = -490/9 which is not equal to zero.

(7+3x) is not factor of (x^3+7x).

HOPE it helps ✔️