3x3-ax2+5x-13 and (a+1)x2-7×+5 leaves the same remainder when divided by (x-3)
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Answer:
a = 2
Step-by-step explanation:
[x³- ax²+ 5x - 13] ÷ (x-3) and [(a+1)x²- 7× +5] ÷ (x-3) leaves the same remainder
by remainder theorem,
=> 3³-a*(3²) + 5*3 -13 = (a+1)*(3²) - 7*3 + 5
=> 27 - 9a + 15 -13 = 9a + 9 - 21 +5
=> 42-13 - 9a = 9a + 14-21
=> 9a+9a = 29 + 7
=> 18a = 36
=> a = 36/18
=> a = 2
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