3x³-x²-10x.Please help me.I cant solve this question.
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Answered by
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HERE'S YOUR ANSWER.....✌️✌️
3x^3 - x^2 -10
= x [ 3x^2 - x - 10 ]
= x [ 3x^2 - ( 6 - 5 )x - 10 ]
= x [ 3x^2 - 6x + 5x - 10 ]
= x [ 3x ( x - 2 ) + 5 ( x - 2 ) ]
= x [ (3x + 5) (x - 2) ]
3x^3 - x^2 -10
= x [ 3x^2 - x - 10 ]
= x [ 3x^2 - ( 6 - 5 )x - 10 ]
= x [ 3x^2 - 6x + 5x - 10 ]
= x [ 3x ( x - 2 ) + 5 ( x - 2 ) ]
= x [ (3x + 5) (x - 2) ]
aadi93:
very well done champ
Answered by
8
HEY HERE IS YOUR ANSWER ☺☺☺
![{3x}^{3} - {x}^{2} - 10x \\ \\ x( {3x}^{2} - {x} - 10) \\ \\ x( {3x}^{2} - 6x + 5x - 10) \\ \\ x(( {3x}^{2} - 6x) + (5x - 10)) \\ \\ x(3x(x - 2) + 5(x - 2)) \\ \\ x(( x - 2)(3x + 5)) \\ \\ x(x - 2)(3x + 5) {3x}^{3} - {x}^{2} - 10x \\ \\ x( {3x}^{2} - {x} - 10) \\ \\ x( {3x}^{2} - 6x + 5x - 10) \\ \\ x(( {3x}^{2} - 6x) + (5x - 10)) \\ \\ x(3x(x - 2) + 5(x - 2)) \\ \\ x(( x - 2)(3x + 5)) \\ \\ x(x - 2)(3x + 5)](https://tex.z-dn.net/?f=+%7B3x%7D%5E%7B3%7D++-++%7Bx%7D%5E%7B2%7D++-+10x+%5C%5C++%5C%5C+x%28+%7B3x%7D%5E%7B2%7D++-++%7Bx%7D+-+10%29+%5C%5C++%5C%5C+x%28+%7B3x%7D%5E%7B2%7D++-+6x+%2B+5x+-+10%29+%5C%5C++%5C%5C+x%28%28+%7B3x%7D%5E%7B2%7D++-+6x%29+%2B+%285x+-+10%29%29+%5C%5C++%5C%5C+x%283x%28x+-+2%29+%2B+5%28x+-+2%29%29+%5C%5C++%5C%5C+x%28%28+x+-+2%29%283x+%2B+5%29%29+%5C%5C++%5C%5C+x%28x+-+2%29%283x+%2B+5%29)
We have factorised in the format :- ax^2 + bx+ c
HOPE IT HELPS ☺☺
PLEASE MARK AS BRAINLIEST
#AADI 93
We have factorised in the format :- ax^2 + bx+ c
HOPE IT HELPS ☺☺
PLEASE MARK AS BRAINLIEST
#AADI 93
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