Question

3x4-13x2+10=0 so find the value of x
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Answer 1

Answer:

x = ±1 Or x = ±√(10/3)

Step-by-step explanation:

$\red { 3x^{4}-13x^{2}+10=0}$

/* Splitting the middle term, we get

$\implies 3x^{4} - 3x^{2} - 10x^{2} + 10 = 0$

$\implies 3x^{2}(x^{2}-1) - 10( x^{2} - 1) =0$

$\implies (x^{2}-1)(3x^{2}-10)=0$

=> x² - 1 = 0 Or 3x² - 10 = 0

=> x² = 1 Or 3x² = 10

=> x = ±1 Or x = ±√(10/3)

Therefore.,

x = ±1 Or x = ±√(10/3)

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Answer 2

$3x^4-13x^2+10=0$

$3x^4-3x^2-10x^2+10$

$3x^2(x^2-1)-10(x^2-1)$

$(x^2-1)(3x^2-10)$

$\boxed{x=1}$ or $\boxed{x^2=\frac{10}{3} \\=x = \sqrt{10/3}}$