Question

3x⁴- 16x³ + 26x² - 16x + 3 = 0 has 4 roots out of which two are equal. Which are these two roots?​

Answer 1

Answer:

3x^4-3x^3-13x^3+13x^2+13x^2-13x-3x+3=0

=>(x-1)(3x^3-13x^2+13x-3)=0

=>(x-1)(3x^3-3x^2-10x^2+10x+3x-3)=0

=>(x-1)(x-1)(3x^2-10x+3)=0

=>(x-1)(x-1)(3x^2-9x-x+3)=0

=>(x-1)(x-1)(x-3)(3x-1)=0

x=1,1,3,1/3 are 4 roots

from which two roots are equal which is 1

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Answer 2

hope this will help you to solve your equation