Math, asked by akhila5126, 10 months ago

3x4+6x3+x2+6x+3=0
Find thw no. of real solutions to the equation.

Answers

Answered by padmasangam
0

Answer:

3×4+6×3+2x+6x+3=0

= 12+18+3+2x+6x=0

= 33+2x+6x=0

= 33+8x=0

= 33=-8x

= 33/8=X

= -4.125=X

now substitute the X value in the equation

3×4+6×3+2x+6x+3=0

= 12+18+2×(-4.125)+6×(-4.125)+3=0

= 12+18+3+(-8.25)+(-24.75)=0

= 33-8.25-24.75=0

= 33-33=0

= 0=0

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