Question

3x4y3– 48y3. = 3y3(x4 – 16). = 3y3[(x2)2 - 42]. = 3y3(x2 + 4)(x2 - 4). = 3y3(x2 + 4)(x2 - 22). = 3y3(x2 + 4)(x + 2)(x -2).

Answer 1

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Answer 2

Answer:

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Step-by-step explanation:

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