Question

[3XO
Question: 6
a. factorise 16x2 - y2 + 4yz - 4z2
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b. The difference between two positive numbers is 4 and the difference between their cubes is
ii. The sum of their squares
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316 find i their product​

Answer 1

Answer:

a) 16 x2-(y2-4yz-4z2)= (4x)2-(y-2z)2

=(4x-(y-2z))(4x+(y-2z))

=(4x-y+2z)(4x+y-2z)

Step-by-step explanation:

b)not written the question properly