3xsquare +2rooy5-5=0 find roots
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Answered by
10
Used method :- middle term splitting!!
Steps are :-
• Multiply the coefficient of x² by the constant term .
Here we get :- 15
• LCM of 15 :- 1 × 3 × 5
• Now , either by adding Or by subtracting the LCM we have to get 2√5
• Here we can subtract √5 from 3√5 to get 2√5.
• [ for the solution refer to the attachment ]
Steps are :-
• Multiply the coefficient of x² by the constant term .
Here we get :- 15
• LCM of 15 :- 1 × 3 × 5
• Now , either by adding Or by subtracting the LCM we have to get 2√5
• Here we can subtract √5 from 3√5 to get 2√5.
• [ for the solution refer to the attachment ]
Attachments:
Answered by
9
3x² + 2√5x - 5
3x² + 3√5x - √5x - 5
3x ( x + √5 ) - √5 ( x + 5 )
( x + √5 ) ( 3x - √5 )
° ( x + √5 ) = 0
x = - √5
• ( 3x - √5 ) = 0
x = √5/3
3x² + 3√5x - √5x - 5
3x ( x + √5 ) - √5 ( x + 5 )
( x + √5 ) ( 3x - √5 )
° ( x + √5 ) = 0
x = - √5
• ( 3x - √5 ) = 0
x = √5/3
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