Question

√3xsquare-5x+2√3=0 using the general formulavand find the solution​

Answer 1

Step-by-step explanation:

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$\sqrt{3} \: {x}^{2} - 5x + 2 \sqrt{3} = 0$

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$\leadsto \sqrt{3} \: {x}^{2} - 5x + 2 \sqrt{3} = 0 \\ \\ comparing \: \: with \: \: a {x}^{2} + bx + c = 0 \\ \\ a = \sqrt{3} \\ b = - 5 \\ c = 2 \sqrt{3} \\ \\ using \: \: quadratic \: \: formula \implies \\ \\ \implies x = \frac{ - b + \: or \: - \sqrt{ {b}^{2} - 4ac} }{2a} \\ \\ \implies x = \frac{5 + \: or \: - \sqrt{25 - 4(2 \sqrt{3} \times \sqrt{3} )} }{2 \sqrt{3} } \\ \\ \implies x = \frac{5 + \: or \: - \sqrt{25 - 24} }{2 \sqrt{3} } \\ \\ \implies x = \frac{5 + \: or \: - 1}{2 \sqrt{3} } \\ \\ \implies x = \frac{\cancel6}{\cancel2 \sqrt{3} } \: \: \: \: or \: \: \: \: x = \frac{\cancel4}{\cancel2 \sqrt{3} } \\ \\ \huge \boxed{ \implies x = \sqrt{3} \: \: \: \: \: or \: \: \: \: \: x = \frac{2}{ \sqrt{3} } }$