Question

3xsquare minus 11x minus 4

Answer 1

Answer:

3x2+11x−4=0

ax2+bx+c=0

Multiply ac to get −12

find factors the multiply to get −12 and add to get the coefficient of the middle term +11

Because we want −12, one factor is negative and the other is positive. Because we want the sum to be +11, the factor with greater absolute value is the positive factor:

List:

−1×12 sum −1+12=11 STOP!, that's the one we want.

Now write the quadratic, replacing the middle term 11x withe the two numbers we just found: −x+12x

3x2−x+12x−4=0 Factor by grouping:

(3x2−x)+(12x−4)=0

x(3x−1)+4(3x−1)=0

(x+4)(3x−1)=0

x+4=0 or 3x−1=0

x=−4 or x=13

The solutions are −4 and 13

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Answer 2

Answer:

(x - 4)(3x + 1)

Step-by-step explanation:

Given that ;

3x² - 11x - 4

We can solve this question by splitting the middle term.

We need two numbers such that their product is (-4 * 3) = (-12) and their sum is (-11). So such two numbers can be (-12) and (1).

3x² - 11x - 4

⇒ 3x² - (12 - 1)x - 4

⇒ 3x² - 12x + x - 4

⇒ 3x(x - 4) + 1( x - 4)

⇒ (x - 4)(3x + 1)

Further, if you need the value of x,

⇒ x - 4 = 0 or 3x + 1 = 0

⇒ x = 4 or x = - 1/3.

_______________________

Hence, the answer is (x- 4)(3x + 1).