Question

3xt5 By = 20
6x-loy = 40
Elimination
method​

Answer 1

Answer:

lm trying......

wait..........

Answer 2

Step-by-step explanation:

$3x + 5y = 20⟹ ⓵\\ 6x - 10y = 40 ⟹⓶\\ \\ (3x + 5y = 20) \times 2⟹ ⓵\\ 6x - 10y = 40 ⟹⓶ \\ \\ 6x + 10y = 20⟹ ⓵\\ 6x - 10y = 40 ⟹⓶ \\ \\ 6x + 10y = 40\\ 6x - 10y = 40 \\ - - - - - - - - \\ 12x = 80 \\ x = \frac{ \cancel{80} _{ \: \: 20} }{ \cancel{12}_{ \: \: 3} } \\ \boxed{ x = \underline{ \underline{ \frac{20}{3} }}} \\ \\ 6x - 10y = 40 \\ ( _{2 \: \: } \cancel 6 \times \frac{20}{ \cancel 3_{ \: \: 1} } ) - 10y = 40 \\ 40 - 10y = 40 \\ - 10y = 40 - 40 \\ - 10y = 0 \\ y = \frac{0}{ - 10} \\ \boxed{y = \underline{ \underline{0}}}$