Question

3xy- 243xy^3 Factorise

Answer 1

Step-by-step explanation:

$3xy - 243x {y}^{3} \\ = 3xy(1 - 81 {y}^{2}) \\ = 3xy[ {(1)}^{2} - {(9y)}^{2} ] \\ = 3xy [(1 + 9y)(1 - 9y)] \\ = 3xy(1 + 9y)(1 - 9y)$

Answer 2

Answer:

3xy - 243xy³

= 3xy (1 - 81xy²)   (By taking common 3xy)

= 3xy (1 + 9xy)(1 - 9xy)  (Splitting the terms)

Checking

3xy (1 + 9xy)(1 - 9xy)

= 3xy {1² + 81xy² + 9xy - 9xy}

= 3xy (1 + 81xy² + 0)

= 3xy (1 + 81xy²)

= (3xy X 1) - (3xy X 81xy²)

= 3xy + (-243xy³)

= 3xy - 243xy³

Therefore your correct answer is 3xy(1 + 9xy)(1 - 9xy)

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