Math, asked by khanguragursharansin, 7 months ago

3xy+4xy+4zx-x²-y²-z² if X=2,y=3 and z=-2

Answers

Answered by tennetiraj86

0

Answer:

answer for the given problem is given

Attachments:

Answered by aswinmurali2006

3

Step-by-step explanation:

3xy+4xy+4zx-x^2-y^2-z^2

= 7xy+4zx-x^2-y^2-z^2

= 7(2*3) -4(2*2) -(2)^2-(3)^2-(-(2))^2

= 7*6 -16 -4-9+4

= 42-16-4-9+4

=17

Hope it helps

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