(3xy2-y3)dx-(2x2y-xy2)dy=0
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I can't understand ur question
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(3xy2 -y3)dx - (2x2y-xy2)dy =0
both side divide by dx
(3xy2-y3)-(2x2y-xy2)dy/dx=0
dy/dx = (3xy2-y3)/(2x2y-xy2)
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