Math, asked by karthikreddy1161, 2 months ago

(3xy2-y3)dx-(2x2y-xy2)dy=0

Answers

Answered by silpa91

0

Answer:

I can't understand ur question

Answered by himanshukashyap0719

0

(3xy2 -y3)dx - (2x2y-xy2)dy =0

both side divide by dx

(3xy2-y3)-(2x2y-xy2)dy/dx=0

dy/dx = (3xy2-y3)/(2x2y-xy2)

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