Question

3y+1/16_2y_3/7=y+3/8+3y_1/14
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Answer 1

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YOUR QUESTION

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$3y + \frac{1}{16} - 2y - \frac{3}{7}=y + \frac{3}{8} + 3y - \frac{1}{14}$

$3y - 2y + \frac{1}{6} - \frac{3}{7} = y + 3y + \frac{3}{8} - \frac{1}{14}$

$1y + \frac{1}{6} - \frac{3}{7} = 4y + \frac{3}{8} - \frac{1}{14}$

$1y + \frac{1 \times 7}{6 \times 7} - \frac{3 \times 6}{7 \times 6}=4y + \frac{3 \times 14}{8 \times 14} - \frac{1 \times 8}{14 \times 8}$

$1y + \frac{7}{42} - \frac{18}{42}=4y + \frac{42}{112} - \frac{8}{112}$

$1y-\frac {11}{42}=4y + \frac{34}{112}$

$1y - 4y = \frac{11}{42} + \frac{34}{112}$

$- 3y = \frac{1232}{4704} + \frac{1424}{4704}$

$- 3y = \frac{2666 \div 2}{4704 \div 2}$

$- 3y = \frac{1333}{2352}$

Answer 2

Step-by-step explanation:

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