3y-1.2 / y+6 = 1/5 Verify also Please answer argent
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is the question like this
( 3y - 1.2) / (y + 6) = 1/5
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Argent
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( 3y - 1.2) / ( y+6) = 1/5 => 5( 3y -1. 2) = y+6 => 15y - 6.0 = y+6=>15y -y = 6+6=>14y = 12=>y = 6/7.
when u will put this value of y = 6/7 in L. H. S. it will be verified.
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3y-1.2 / y+6 = 1/5
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