Question

(3y - 1)/4 + (2y + 3)/3 = (1 - 7y)/6

Please solve this you have to find the value of 'y' and i mark you as brainlist ​

Answer 1

$y = \frac{ - 7}{31}$

Step-by-step explanation:

$Given, \: \: \frac{3y - 1}{4} + \frac{2y + 3}{3} = \frac{1 - 7y}{6} \\ \frac{3(3y - 1) + 4(2y + 3)}{12} = \frac{1 - 7y}{6} \\ \frac{9y - 3 + 8y + 12}{12} = \frac{1 - 7y}{6} \\ \frac{17y + 9}{12} = \frac{1 - 7y}{6} \\ \frac{17y + 9}{2} = 1 - 7y \\ 17y + 9 = 2(1 - 7y) \\ 17y + 9 = 2 - 14y \\ 17y + 14y = 2 - 9 \\ 31y = - 7 \\ \boxed{ y = \frac{ - 7}{31} }$