Math, asked by Amreengill, 11 months ago

(3y-1) by 4+(2y+3) by 3=(1-7y) by 6 verify​

Answers

Answered by jacksonle
1

Answer:

3(2y + 3) + 6(3y + -1) = 1 + -7y

Reorder the terms:

3(3 + 2y) + 6(3y + -1) = 1 + -7y

(3 * 3 + 2y * 3) + 6(3y + -1) = 1 + -7y

(9 + 6y) + 6(3y + -1) = 1 + -7y

Reorder the terms:

9 + 6y + 6(-1 + 3y) = 1 + -7y

9 + 6y + (-1 * 6 + 3y * 6) = 1 + -7y

9 + 6y + (-6 + 18y) = 1 + -7y

Reorder the terms:

9 + -6 + 6y + 18y = 1 + -7y

Combine like terms: 9 + -6 = 3

3 + 6y + 18y = 1 + -7y

Combine like terms: 6y + 18y = 24y

3 + 24y = 1 + -7y

Solving

3 + 24y = 1 + -7y

Solving for variable 'y'.

Move all terms containing y to the left, all other terms to the right.

Add '7y' to each side of the equation.

3 + 24y + 7y = 1 + -7y + 7y

Combine like terms: 24y + 7y = 31y

3 + 31y = 1 + -7y + 7y

Combine like terms: -7y + 7y = 0

3 + 31y = 1 + 0

3 + 31y = 1

Add '-3' to each side of the equation.

3 + -3 + 31y = 1 + -3

Combine like terms: 3 + -3 = 0

0 + 31y = 1 + -3

31y = 1 + -3

Combine like terms: 1 + -3 = -2

31y = -2

Divide each side by '31'.

y = -0.06451612903

Simplifying

y = -0.0645161290

Step-by-step explanation:

Answered by jayantkora7
3

Answer:

-7/31

y=-7/31 verification LHS=RHS

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