3y-11=0,6x+7y-5=0 substituting method
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Answer:
x= -31/9, y= 11/3
Step-by-step explanation:
3y - 11 = 0 ------eq(i)
6x + 7y - 5 = 0 -------eq(ii)
Substituting y from eq(i), we get
y = 11/3
Putting value of y in eq(ii), we get,
6x + 7*11/3 -5 =0
6x = 5 - 77/3
6x = (15-77)/3 = -62/3
x = -62/18 = -31/9
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