(3y+11)(3y+11)
do it by suitable identity
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Step-by-step explanation:
(3y+11)(3y+11)=(3y+11)²
As we know that (a+b)²=a²+b²+2ab
(3y+11)²
=(3y)²+(11)²+2×3y×11
=9y²+121+66y
=9y²+66y+121
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