3y^-17y-6=0
Give me solution
Answers
Answered by
0
3y^-17y-6=0
3y^-18y+1y-6=0
3y(y-6)+1(y-6)=0
(3y+1)(y-6)=0
3y+1=0or y-6=0
3y=-1 or y=6
y=-1/3 or y=6
so y=6
3y^-18y+1y-6=0
3y(y-6)+1(y-6)=0
(3y+1)(y-6)=0
3y+1=0or y-6=0
3y=-1 or y=6
y=-1/3 or y=6
so y=6
Similar questions
Social Sciences,
7 months ago
Economy,
7 months ago
Geography,
1 year ago
English,
1 year ago
CBSE BOARD X,
1 year ago