Question

-3y^2 + 10y - 16 and 7y^2 + 8
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Answer 1

Step-by-step explanation:

Step 1: Subtract 7y^2+8 from both sides.

−3y2+10y−16−(7y2+8)=7y2+8−(7y2+8)

−10y2+10y−24=0

Step 2: Use quadratic formula with a=-10, b=10, c=-24.

y=−b±√b2−4ac2a

y=−(10)±√(10)2−4(−10)(−24)2(−10)

y=−10±√−860−20