Math, asked by sowmyasonu, 1 year ago

3y^2-10y+9=0 plz solve the quadratic problem​

Answers

Answered by Apache191201
3

Answer:

the roots of the equation are irrational and distinct

Step-by-step explanation:

D=(b^2-4ac)^(1/2)

D=-ve

x=(-b+-D^1/2)÷2a

Answered by master55538
3

Answer:

the answer is

wait

we should get 18y2 or

simply applying formula

-b+-root over b square - 4ac / 2a

then 10+-root over -8/6

5+root8*i/3 or 5-root8*i/3

are the roots of the equation

we can check by b2-4ac=0

100-4(3)*(9)=0

100-108=0

-8is less than 0 so the zeros are imaginary

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