3y^2-10y+9=0 plz solve the quadratic problem
Answers
Answered by
3
Answer:
the roots of the equation are irrational and distinct
Step-by-step explanation:
D=(b^2-4ac)^(1/2)
D=-ve
x=(-b+-D^1/2)÷2a
Answered by
3
Answer:
the answer is
wait
we should get 18y2 or
simply applying formula
-b+-root over b square - 4ac / 2a
then 10+-root over -8/6
5+root8*i/3 or 5-root8*i/3
are the roots of the equation
we can check by b2-4ac=0
100-4(3)*(9)=0
100-108=0
-8is less than 0 so the zeros are imaginary
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