Math, asked by rinku192113114, 11 months ago

3y-2÷3+(2y+3)÷3=y+7÷6​

Answers

Answered by Anonymous
4

Answer:

5/24

Step-by-step explanation:

3y - 2 ÷ 3 + ( 2y + 3 ) ÷ 3 = y + 7 ÷ 6

=> 3y - 2 ÷ 3 + 2y + 3 ÷ 3 = y +7 ÷ 6

=> 3y - 2/3 + 2y + 1 = y + 7/6

=> 3y + 2y - y = 7/6 + 2/3 - 1

=> 4y = 7/6 + 4/6 - 1

=> 4y = 11/6 - 1

=> 4y = 11/6 - 6/6 = 5/6

=> y = 5/6×4

=> y = 5/24

Hope this helps uh........

Be brainly

Answered by parul682
0

Answer:

3y-2/3+(2y+3)/3=y+7/6

(2y+3)/3=y-3y+7/6+2/3

(2y+ 3)/3=-2y+7/6+2/3

(2y+ 3)/3=(-12y+7+4)/6

(2y + 3)/3=(-12y+11)/6

cross multiply

6 (2y+3)=3 (-12y+11)

12y+18=-36y+33

12y+36y=33-18

48y =15

y=15/48Ans

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