Question

(3y-2)/3+(2y+3)/3=(y+7)/6

Answer 1

Answer:

-1/3 is the answer

Hope it helps you

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Answer 2

Given :-

$\sf{\frac{3y-2}{3}+{\frac{2y+3}{3}\:=\: \frac{y+7}{6}}}$

To find :-

$\sf{Value\: of\:y }$

Solution :-

$\sf{\frac{3y-2}{3}+{\frac{2y+3}{3}\:=\: \frac{y+7}{6}}}$

$\sf{\frac{3y-2+2y+3}{3}\:=\: \frac{y+7}{6}}$

$\sf{\frac{5y+1}{\cancel{3}}\:=\: \frac{y+7}{\cancel{6}}}$

$\sf{5y+1\:=\: \frac{y+7}{2}}$

$\sf{2 \times ( 5y+1 )\:=\: y+7}$

$\sf{10y+2\:=\:y+7}$

$\sf{10y-y\:=\:7-2}$

$\sf{9y\:=\:5}$

$\sf{y\:=\: \frac{5}{9}}$

$\bf{ \boxed{Thanks}}$