Question

3y^2+34y+11=0 factorise the quadratic equation ​

Answer 1

Answer:

(3y+1)(y+11) is the answer...

y= -1/3, -11 are both the answer.

Answer 2

Answer:

$3y^2+34y+11=0\\=>3y^2+y+33y+11=0\\=>y(3y+1)+11(3y+1)=0\\=>(3y+1)(y+11)=0\\Therefore, \\Either,y+11=0\\=>y=-11\\Or,3y+1=0\\=>3y=-1\\=>y=-1/3$

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