Question

3y^2+4y+1=0 then form equation whose roots are alpha^2 & beta^2​

Answer 1

Answer:

Step-by-step explanation:

3y²+4y+1=0

3y²+3y+y+1=0

3y(y+1)+(y+1)=0

(3y+1)(y+1)=0

3y+1= 0 OR y+1=0

Y= -1/3 or y=-1