Question

3Y^2-y-2=0 then find the value of y

Answer 1

Answer:

$\bf\large your \: ans = (1 \: and \: \frac{ - 2}{3})$

Step-by-step explanation:

$\sf\huge {3y}^{2} - y - 2 \\ \\ \sf\underline{using\: splitting \:the \: middle \:term \: method } \\ \\ \sf\ \implies: {3y}^{2} - (3y - 2y) - 2 = 0 \\ \\ \sf\ \implies: {3y}^{2} - 3y + 2y - 2 = 0 \\ \\ \sf\ \implies: 3y(y - 1) + 2(y - 1) = 0 \\ \\ \sf\ \implies: (3y + 2)(y - 1) = 0 \\ \\ \bf\ 3y + 2 = 0 \\ \sf\boxed{ \implies:y = \frac{ - 2}{3} } \\ \\ \bf\ y - 1 = 0 \\ \\ \sf\boxed{ \implies: y = 1}$

Answer 2

Answer:

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