Question

3y^2+y^3+3+y please help me out ​

Answer 1

Step-by-step explanation:

Given that: y

3

−3y

2

+2y−6−xy+3x

=(y

3

−3y

2

)+(2y−6)+(−xy+3x), (group pair of terms)

=y

2

(y−3)+2(y−3)−x(y−3), (factor each binomials)

=(y−3)(y

2

+2−x) , (factor out common factor (y−3))

The common factors of y

3

−3y

2

+2y−6−xy+3x are (y−3)(y

2

+2−x)

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