Question

3y – 2x = 7, 5x + 3 = -7 (x, y) is

Answer 1

$\displaystyle\sf{Given,$

$\displaystyle\sf{3y-2x=7\:\:\:---(1)$

$\displaystyle\sf{5x+3=-7\:\:\:---(2)$

$\displaystyle\sf{From \:(2),$

$\displaystyle\sf{\implies5x=-7-3$

$\displaystyle\sf{\implies 5x=-10$

$\displaystyle\sf{\implies x=\frac{-10}{5}$

$\displaystyle\sf{\implies x=-2$

$\displaystyle\sf{Substituting\:the\:value\:of\:x\:in\:(1)$

$\displaystyle\sf{\implies 3y-2(-2)=7$

$\displaystyle\sf{\implies3y+4=7$

$\displaystyle\sf{\implies 3y=7-4$

$\displaystyle\sf{\implies 3y=3$

$\displaystyle\sf{\implies y=\frac{3}{3}$

$\displaystyle\sf{\implies y=1$

$\boxed{\displaystyle\sf{\therefore\:(x,y)=(-2,1)}}$

Answer 2

$\rm\longrightarrow 5x+3=-7\\\\\longrightarrow 5x=-7-3\\\\\longrightarrow 5x=-10\\\\\longrightarrow\bf\underline{ x=-2 }$

$\rm Substituting \ the \ value \ of \ x \ in \ the \ equation \ \bf{3y-2x=7} \ .\\\\\rm\longrightarrow 3y-2\times(-2)=7\\\\\longrightarrow 3y+4=7\\\\\longrightarrow 3y=7-4\\\\\longrightarrow\bf\underline{ y=1}$

$\bf\boxed{\boxed{\bf (x \ , \ y )=(-2 \ , \ 1)}}$

$\rm\bf HOPE \ IT \ HELPS \ U \ ....................$