Question

3y+4=0 give two solution for this equation

Answer 1

y = -4 / 3 is the answer, because 4 will come on RHS and so -4

Answer 2

Given Equation is 3y + 4 = 0.  

It can be written as 3y + 0x + 4 = 0  ---- (1)

Substitute x = 0 in (1), we get

3y + 0(0) + 4 = 0

3y + 4 = 0

3y = -4

y = -4/3.

Therefore one solution is (0,-4/3).


Substitute x = 1 in (1), we get

3y + 0(1) + 4 = 0

3y + 4 = 0

y = -4/3.

Therefore another solution is (1,-4/3).


Hope this helps!