Question

3y/4-1/4(y-20) = y/4+32​

Answer 1

Step-by-step explanation:

$= > \frac{3y}{4} - \frac{1}{4} (y - 20) = \frac{y}{4} + 32 \\ \\ => \frac{3y}{4} - \frac{y}{4} + \frac{20}{4} = \frac{y + 128}{4} \\ \\ => \frac{3y - y + 20}{4} = \frac{y + 128}{4} \\ \\ => 2y + 20 = y + 128 \\ => 2y - y = 128 - 20 \\ => y = 108.$

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