Question

3y+4=5y-4 in transporting method


I hope you now can you tell me please ​

Answer 1

Step-by-step explanation:

3y-5y = -4-4

2y = -8

y = -4

hope it help

Answer 2

Answer :-

• The value of y is 4.

Step-by-step explanation :-

$\sf Q) \: 3y + 4 = 5y - 4$

Putting the variables and the constants on different sides, by transposing,

$\sf\Rightarrow3y - 5y = - 4 - 4$

On simplifying,

$\sf \Rightarrow - 2y = - 8$

Transposing - 2 from LHS to RHS, changing it's sign,

$\sf \Rightarrow y = \dfrac{ - 8}{ - 2}$

Dividing - 8 by - 2,

$\sf \Rightarrow y = 4.$

Therefore, the value of y is 4.

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Verification :-

To check our answer, let's put 4 (The value of y) in place of y and see whether LHS = RHS.

Let's proceed!

LHS

$\sf \Rightarrow 3y + 4$

Replacing y with 4,

$\sf \Rightarrow 3 \times 4 + 4$

Applying the BODMAS rule and multiplying the numbers first,

$\sf \Rightarrow 12 + 4$

Adding the numbers,

$\sf \Rightarrow 16.$

RHS

$\sf \Rightarrow 5y - 4$

Replacing y with 4,

$\sf \Rightarrow 5 \times 4 - 4$

Applying the BODMAS rule and multiplying the numbers first,

$\sf \Rightarrow 20 - 4$

Subtracting the numbers,

$\sf \Rightarrow 16.$

Since LHS = RHS,

Hence verified!

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