3y+4=5y–4,Solve the given equation by transposing the terms and check your result.
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Answered by
119
Hi ,
Given linear equation in variable y is
3y + 4 = 5y - 4
=> 5y - 4 = 3y + 4
add 4 both sides of the equation
=> 5y - 4 + 4 = 3y + 4 + 4
=> 5y = 3y + 8
subtract 3y from both sides of the
equation ,
=> 5y - 3y = 3y - 3y + 8
=> 2y = 8
divide each term with 2 , we get
=> 2y/2 = 8/2
=> y = 4
Verification :
Substitute y = 4 in given equation ,
LHS = 3×4 + 4 = 16
RHS = 5×4 - 4 = 16
Therefore ,
LHS = RHS
I hope this helps you.
: )
Given linear equation in variable y is
3y + 4 = 5y - 4
=> 5y - 4 = 3y + 4
add 4 both sides of the equation
=> 5y - 4 + 4 = 3y + 4 + 4
=> 5y = 3y + 8
subtract 3y from both sides of the
equation ,
=> 5y - 3y = 3y - 3y + 8
=> 2y = 8
divide each term with 2 , we get
=> 2y/2 = 8/2
=> y = 4
Verification :
Substitute y = 4 in given equation ,
LHS = 3×4 + 4 = 16
RHS = 5×4 - 4 = 16
Therefore ,
LHS = RHS
I hope this helps you.
: )
Answered by
0
Answer:
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