Question

-3y(4y+3x)+2x(x^2-y^2)​

Answer 1

Answer: => 3x - 12y - 4y + 3x - (4x - 2y)(2x - 2y)

=> 3x - 12y - 4y + 3x - 8x^2 - 4y + 4y

=> 8x^2 + 3x + 3x - 12y - 4y - 4y + 4y

=> 8x^2 + 6x - 16y

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Answer 2

Answer:

3y(4y+3x)+2x(x²-y²)

-3y(4y+3x)+2x(x²-y²)=-12y²-9xy+2x³-2xy²

Step-by-step explanation:

-3y(4y+3x)+2x(x²-y²)

= -3y×4y+(-3y)(3x)+2x×x²-2x×y²

= -12y²-9xy+2x³-2xy²

Therefore,

-3y(4y+3x)+2x(x²-y²)

=-12y²-9xy+2x³-2xy²