(3y+5)/5 - (5y-7)/6 = (y-2)/3
Answers
Answered by
1
Answer:
(3y/5)-(5y-7)/6=y-2/3
6(3y+5)-5(5y-7) by taking LCM of 5 and 6
18y+30-25y+35=y-2/3
3(-7y+65)=30(y-2) by cross multiplication.
-21y+65=30y-60
65+60=30y+21y
51y=125
y=125/51
Answered by
0
Answer:
3y+5-5y-7=[y-2]/3 .5.6
3y+5-5y-7=10y-20
3y-5y=10y-20-5+7
-2y-10y=-20-5+7
-12y=-25+7
12y=-18
y= -18/-12
y= -3/2
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