3y = 72 +y²
Find the value of y
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it is a quadratic equation...
so
3y=72+y²
0=y²–3y+72
y²–3y+72= 0
using the above quadratic formula... where
x=y
a=1
b=(-3)
c=72
we get...
y=7 or 10
plz see attached photo...
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