Math, asked by konmoni, 9 months ago

(3y_8) × (5y_1)find each of the following product​

Answers

Answered by vaishnavitiwari1041
1

Answer:

Here's your answer

(3y  -  8)(5y - 1) = 0 \\  \\ 3y(5y - 1) - 8(5y - 1) = 0 \\  \\ 15 {y}^{2}  - 3y - 40y + 8 = 0 \\  \\ 15 {y}^{2}  - 43y +  8= 0 \\  \\  \\  \\

Hope it helps

Answered by vaniaidham
1

Answer:

(3y_8) × (5y_1)

=3y(5y-1)8(5y-1)

=(15y-3y+40y-18)

=52y-18

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