3y minus 5 upon5 minus 2brackety minus 5)=y minus 1 upon2
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Answer:
Hey mate;
Step-by-step explanation:
3y-5/5-2(y-5)=y-1/2
3y-5/5-2y+10=y-1/2
3y-5/5-2y=y-1/2
3y-5=(5-2y)×(y-1/2)
3y-5=p-5y+2y²/2
2(3y-5)=5y+2y²
6y-10=5y+2y²
2y²-y+10
=2y²-5y+4y+10
= 2y(y+2)-5(y+2)
= 2y-5, y+2
= y=5/2, -2
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