Math, asked by prasannrock27, 11 months ago

3y square _20y_23=0​

Answers

Answered by mandip61
2

Answer:

3Y-23=0 | Y+1=0

Y=23/3 | Y=-1

Step-by-step explanation:

3y  {}^{2} - 20y - 23 = 0

3y {}^{2}  - (23 - 3)y - 23 = 0 \\ 3y {}^{2}  - 23y + 3y - 23 = 0 \\ y(3y - 23) + (3y - 23) = 0 \\ (3y - 23)(y + 1) = 0 \\

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