Question

3y² - 25y - 18 please tell me how to solve​

Answer 1

Answer:

$3 {y}^{2} - 27y + 2y - 18 \\ = 3y(y - 9) + 2(y - 9) \\ = (y - 9)(3y + 2) \\ so \\ y = 9 \\ y = \frac{ - 2}{3}$

which is the required ans

Answer 2

Answer:

First multiple the coefficient of y² with the constant

3*8=54

Now we have to find the factors of 54 such that their

addition or subtraction will give the middle term.

27*2 is 54 and 27-2=25 ie the middle term

Thus we split the middle term in the following way:

3y² - 25y - 18

3y²-27y+2y-18

3y(y-9) +2(y-9)

3y² - 25y - 18 can be factorised into (3y+2) (y-9)

This is your answer:

(3y+2) (y-9)