3y²-2y-1=0 solve the quadratic equation by factorisation
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Answer:
3×-1=-3
-3+1=-2
3y^2-3y+1y-1=0
3y(1y-1) +1(1y-1) =0
(3y+1) (1y-1) =0
y=-1/3; y=1/1
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