3y²+4y-15
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Answered by
0
Answer:
3y²+4y-15
3y²+5y-9y-15
y(3y+5)-3(3y+5)
(3y+5)(y-3)
Answered by
5
Answer :
- Zeros of the quadratic polynomial are 5/3 and -3 respectively.
Given :
- A quadratic polynomial 3y² + 4y - 15.
To Find :
- Zeroes of the quadratic polynomial.
Solution :
Firstly we'll write the equation
- 3y² + 4y - 15
Split the middle term
- 3y² + 9y - 5y - 15
Take common
- 3y (y + 3) - 5 (y + 3)
Arrange them together
- (3y - 5) (y + 3)
Equate with 0
______________
→ 3y - 5 = 0
→ 3y = 5
→ y = 5/3
→ y + 3 = 0
→ y = 0 - 3
→ y = -3
______________
Hence, the zeroes of the quadratic polynomial are 5/3 and -3 respectively.
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