Question

3y2 - 4y + k = 0
What is value of k

Answer 1

$k = 4y - 3 {y}^{2}$

hope it is useful.....

Answer 2

$<strong> </strong><strong>\</strong><strong>tt</strong><strong> </strong><strong> </strong><strong>3y</strong><strong>^</strong><strong>2</strong><strong> </strong><strong>-</strong><strong> </strong><strong>4y</strong><strong> </strong><strong>+</strong><strong> </strong><strong>k</strong><strong> </strong><strong>=</strong><strong> </strong><strong>0</strong><strong> </strong><strong>[</strong><strong>/</strong><strong>tex</strong><strong>]</strong></p><p><strong>\\ </strong><strong>\</strong><strong>\</strong></p><p><strong> </strong><strong>[tex] \</strong><strong>t</strong><strong>e</strong><strong>x</strong><strong>t</strong><strong>tt</strong><strong> </strong><strong> </strong><strong>{</strong><strong>comparing</strong><strong> </strong><strong>with</strong><strong> </strong><strong> </strong><strong>ax</strong><strong>^</strong><strong>2</strong><strong> </strong><strong>+</strong><strong> </strong><strong>bx</strong><strong> </strong><strong>+</strong><strong> </strong><strong>c</strong><strong> </strong><strong>=</strong><strong> </strong><strong>0</strong><strong> </strong><strong>}</strong><strong> </strong><strong>[</strong><strong>/</strong><strong>tex]</strong></p><p><strong> </strong><strong>\\ \\</strong></p><p><strong> [tex] \tt</strong><strong> </strong><strong>\</strong><strong>therefore</strong><strong> </strong><strong>a</strong><strong> </strong><strong>=</strong><strong> </strong><strong>3</strong><strong> </strong><strong>,</strong><strong> </strong><strong>b</strong><strong> </strong><strong>=</strong><strong> </strong><strong>-4</strong><strong>,</strong><strong> </strong><strong>c</strong><strong> </strong><strong>=</strong><strong> </strong><strong>k</strong><strong>$

\\ \\

$\tt</strong><strong> </strong><strong>now</strong><strong>,</strong><strong> </strong><strong>\:</strong><strong> </strong><strong>b</strong><strong>^</strong><strong>2</strong><strong> </strong><strong>-</strong><strong> </strong><strong>4ac</strong><strong> </strong><strong>=</strong><strong> </strong><strong>0</strong><strong>$

\\ \\

$\tt </strong><strong> </strong><strong>0</strong><strong> </strong><strong>=</strong><strong> </strong><strong>(</strong><strong>-4</strong><strong>)</strong><strong>^</strong><strong>2</strong><strong> </strong><strong>-</strong><strong> </strong><strong>4</strong><strong> </strong><strong>\</strong><strong>times</strong><strong> </strong><strong>3</strong><strong> </strong><strong>\</strong><strong>times</strong><strong> </strong><strong>k</strong><strong> </strong><strong>$

\\ \\

$\tt</strong><strong> </strong><strong>\</strong><strong>implies</strong><strong> </strong><strong>0</strong><strong> </strong><strong>=</strong><strong> </strong><strong>1</strong><strong>6</strong><strong> </strong><strong>-</strong><strong> </strong><strong>12k</strong><strong>$

\\ \\

$\tt </strong><strong>\</strong><strong>implies</strong><strong> </strong><strong>12k</strong><strong> </strong><strong>=</strong><strong> </strong><strong>1</strong><strong>6</strong><strong> </strong><strong>$

\\ \\

$\tt</strong><strong> </strong><strong>\</strong><strong>implies</strong><strong> </strong><strong>k</strong><strong> </strong><strong>=</strong><strong> </strong><strong>\</strong><strong>frac</strong><strong>{</strong><strong>16</strong><strong>}</strong><strong>{</strong><strong>1</strong><strong>2</strong><strong>}</strong><strong> </strong><strong>=</strong><strong> </strong><strong>\</strong><strong>frac</strong><strong>{</strong><strong>4</strong><strong>}</strong><strong>{</strong><strong>3</strong><strong>}</strong><strong>$