Math, asked by sanjay8147, 10 months ago

3y2_7y=0 and please solve this problem

Answers

Answered by kamleshgyan72

1

y = 0 , 7/3

3y^2 - 7y = 0

y ( 3y - 7 ) = 0

y = 0. or. 3y - 7 = 0

y = 0. or. 3y = 7

y = 0. or. y = 7/3

therefore,

y = 0 , 7/3

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