Question

3y²+7y+4=0 can anyone solve this quadratic equation formula

Answer 1

Step-by-step explanation:

By factorization method

3y²+7y+4=0

3y²+(3+4)y+4=0

3y²+3y+4y+4=0

3y(y+1)+4(y+1)=0

(y+1)(3y+4)=0

if y+1=0

y=-1

if 3y+4=0

y=-4/3

[y=-1,-4/3]

hope it helps you

Answer 2

Answer:

y=-1 OR y=-4/3

Step-by-step explanation:

i hope this is helpful for you