Question

3y²-y-10 solve using factorisation method ​

Answer 1

Answer:

${(3y)}^{2} - y - 10 \\ \\ 3y {}^{2} - 6y + 5y - 10 \\ 3y(y - 2) \: 5(y - 2) \\ (3y + 5) \: (y - 2)$

( 3y + 5 ) ( y - 2 )

y = -5 / 3

y = 2

Answer 2

Answer:

(3y+5)(y-2)

Step-by-step explanation:

3y²-y-10                                  (Split the Middle term)

3y²-6y+5y-10                          (Take out the common terms)

3y(y-2)+5(y-2)

(3y+5)(y-2)

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