Question

3ysquare +17y -56 = 0 solve using factorisation​

Answer 1

Answer:

3y² + 17y -56 = 0

3y² + 24y - 7y -56 = 0

3y ( y + 8) -7 ( y + 8 ) = 0

( 3y - 7) ( y + 8) = 0

If 3y -7 = 0

y = $\frac{7}{3}$

If y + 8 = 0

y = -8

Hence, y = -8, $\frac{7}{3}$

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Answer 2

• Use the sum-product pattern

${3y}^{2} + 17y - 56 = 0 \\ {3y}^{2} + 24y - 7y - 56 = 0$

• Common factor from the two pairs

$( {3y}^{2} + 24y) + ( - 7y - 56) = 0 \\ 3y(y + 8) - 7(y + 8) = 0$

• Rewrite in factored form

$3y(y + 8) - 7(y + 8) = 0 \\ (3y - 7)(y + 8) = 0$

• Create separate equations

$(3y - 7)(y + 8) = 0 \\ = 3y - 7 = 0 \\ = y + 8 = 0$

• Rearrange and isolate the variable to find each solution

$y = \frac{7}{3} \\ y = (- 8)$

• Solution

$y = \frac{7}{3} \\ y = ( - 8)$