Question

3yz(a-b-c) - 3z(a - b-c) +2127a-b-) C​

Answer 1

Answer:

(a - b - c)²

= (a - b - c)(a - b - c)

= a² - ab - ac - ab + b² + bc - ac + bc + c²

= a² + b² + c² - 2ab + 2bc - 2ac

Similarly, the formula of (a ± b ± c)² is in the form of a² + b² + c² ± 2ab ± 2bc ± 2ac. As you can see, a x -b = -ab, -b x -c = bc, and a x -c = -ac. Then just plug it in to the above form to get

a² + b² + c² - 2ab + 2bc - 2ac.

(a - b - c)² = a² + b² + c² - 2ab + 2bc - 2ac

That is the faster way.

Hope this helps!

Step-by-step explanation:

Answer 2

Answer:

3yz -3z+ 2127+ abc

Step-by-step explanation:

thanks